我就废话不多说了,大家还是直接看代码吧~
>>> import re >>> subject = '080045000106309140003F2F7D100A0A3C0A0A0A3D0A00000800450000EE000000003F06CCF0C0A8C864C0A8646400000000000000000000000050000000F7410000' >>> result = re.sub(r"(?<=\w)(?=(?:\w\w)+$)", " ", subject) >>> result '08 00 45 00 01 06 30 91 40 00 3F 2F 7D 10 0A 0A 3C 0A 0A 0A 3D 0A 00 00 08 00 45 00 00 EE 00 00 00 00 3F 06 CC F0 C0 A8 C8 64 C0 A8 64 64 00 00 00 00 00 00 00 00 00 00 00 00 50 00 00 00 F7 41 00 00'
补充:python 字符串输出时 使用空格隔开
使用python 中的join函数, 即可实现
In [77]: test = "12344345345" In [78]: test Out[78]: '12344345345' In [79]: result = " ".join(test) In [80]: result Out[80]: '1 2 3 4 4 3 4 5 3 4 5'
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